Sheila's Textbook Questions

A) Alex is thinking of the number 60.

B) No, there is only one answer. The number must be between 40 and 64. The only multiple of 12 in the range 60.

16) A fitness center will install a square hot tub in a 6m x 6m room. They want the tub to fill no more than 75% of the room area.

A) What is the maximum area of the hot tub ?

27m2

B) What dimensions , to the tenth of a meter , will the fitness center order from the manufacturer? Explain.

The fitness center should get a 5.1m by 5.1m so that it doesn't go over the available space.

Here is a link of square roots.

Sorry i couldn't get the video up so here's a link instead.

ENJOY!

1. The relationship between the lengths of the sides of a right triangle. The sum of the areas of the squares attached to the legs of a right triangle equals the area of the square attached to the hypotenuse3232. a + b = c

2.Solve the missing side lenght.

3. Is this a right triangle? Prove it.

Aaron's textbook questions

a) The area of the picture is 324cm squared, because 18cm x 18 = 324'

b) The area of the board is 1296 cm squared, 324x4 = 1296

c) The dimensions of the board is 36 cm by 36 cm, because the square root of 1296 is 36.

The order of the numbers is √27, 5.8, 6.3,√46 , 7. 27 is first because √27= 5.1 which is smaller than 5.8. 5.8 is second because 6.3 is higher than 5.8. 6.3 is third because √46= 6.7 which is higher than 6.3. √46 is fourth because its higher than 6.3, √46= 6.7. 7 is last because all the other numbers are lower than it and no other number is higher than it.

a) the maximum area of the hot tub is 27m squared because 25% of 36 is 9 and 9x3 = 27 which is 75%.

b) the fitness center should order 5.1m by 5.1m because √27 = 5.1 , and they cant go over 75% of their space.

Here is a video to help you

www.youtube.com/watch?v=NNHlnh7AURM

Irena's Textbook Questions

Here's a link on square roots.

Here's a video on square roots.

1. Answer in a short paragraph and with diagrams.

Pythagorean Relationship:

The relationship between the lengths of the sides of a right triangle. The sum of the areas of the squares attached to the legs of a right triangle equals the area of the square attached to the hypotenuse. 2 2 2

a + b = c

2. Solve the missing side length

3. Is this a right triangle? Prove it!

No it is not a right triangle. It is not a right triangle because the sum of the areas of the squares of the legs are not equal to the area of the square of the hypotenuse.

Randolph's Textbook Questions 4, 12, 15

I'm gonna answer those three questions are 4, 13, and 15 from the textbook.







You need help? This video will help you!

http://www.youtube.com/watch?v=iFPsqk8MYj0

Nikka's textbook questions 5, 10, 14

B. No, there is no more then 1 answer because, there is no multiple of 12 between the perfect squares of 49 and 64.

Here's some games you can play (:

http://www.math-play.com/square-roots-game.html

http://www.funbrain.com/cgi-bin/ttt.cgi?A1=s&A2=24&A3=0

Pythagorean Relationship

1.

A pythagorean relationship means the sum of the areas of the two shortest sides of a right angle triangle (a and b), and it must always equal to the area of the hypotenus (c).

2.

^= squared.

a^+b^=c^

12^+5^=c^

(12x12)+(5x5)=c^

144+25=c^

169=c^

root 169=root c^

13cm=c^

The hypotenuse is 13cm.

3.

=/ = does not equal.

a^+b^=11^

(8x8)+(6x6)=(11x11)

64+36=121

100=/121

No it is not a right triangle because, the legs does not equal the hypotenuse.

Beverly's textbook Questions 4, 10, 14

B) No, there is no more then 1 answer because there is no multiple of 12 betwee

n the two perfect squares 49 and 64.

Here is a video and a link video to help you out (:

1. Answer in a short paragraph and with diagrams

The relationship between the lengths of the sides of a right triangle. The sum of the area of the squares attached to the legs of a right triangle equals the area of the square attached to the hypotenuse.

2. Solve the missing side length.

3. Is this a right triangle? Prove it !

No, it is not a right triangle because both of the legs do not equal the hypotenus.